86. KE = 1/2mv^2 = .5(10)(10)^2 = 500J
87. F = ma = m (change in v/change in t) = m (10/4) = 25N
88. Change in KE = F*d --> 500J = 25 * d --> d = 50m
89. (1) Less
90. (2) increases
91. (1) less than h
92. It would look like a graph of y = x^2, a parabola
93. KE = .5(1)(100) = 50J; 50 = 1*10*d --> d = 5m
Subscribe to:
Post Comments (Atom)
No comments:
Post a Comment