Wednesday, December 19, 2007

Homework Solutions 12/19

86. KE = 1/2mv^2 = .5(10)(10)^2 = 500J
87. F = ma = m (change in v/change in t) = m (10/4) = 25N
88. Change in KE = F*d --> 500J = 25 * d --> d = 50m
89. (1) Less
90. (2) increases
91. (1) less than h
92. It would look like a graph of y = x^2, a parabola
93. KE = .5(1)(100) = 50J; 50 = 1*10*d --> d = 5m

Exam 6 Review Sheet Solution

1. 70N
2. 300J
3. half as great
4. 300W
5. 800J
6. 10J
7. quadruples
8. 125J
9. BC
10. 3J

Monday, December 17, 2007

Homework - Week of 12/17

Monday: TPS p89 77-85
Tuesday: TPS p90 86-93
Wednesday: STUDY!!! (tutoring session Wednesday period 5 in room 606)
Friday: Take home Regents exam for the break

Answers to Friday's Review Sheet

1. D
2. B
3. A
4. C
5. D
6. B
7. C
8. C
9. C
10. D
11. D
12. C
13. A
14. C
15. B
16. A
17. A
18. D
19. D
29. A
21. D
22. A
23. A
24. C
25. A
26. B
27. A
28. D
29. D
30. C
31. C
32. D
33. B
34. B
35. D
36. A
37. D
38. B
39. A
40. C
41. B
42. A
43. D
44. A

Thursday, December 13, 2007

For Monday's Lab

1. The energy lab is due
2. Bring your structural support materials for your roller coaster